System of Equations Solver –
Solve Linear Systems Step by Step

Free, instant solutions for 2×2 and 3×3 systems using substitution, elimination, and matrix methods.

What Is a System of Equations?

The solution is where the two lines intersect — the point that satisfies both equations simultaneously.

A system of equations is a collection of two or more equations that share the same set of unknowns. The goal of a linear system solver is to find values for those unknowns that satisfy every equation at once — in geometric terms, the point (or points) where the equations’ graphs intersect.

Linear systems appear everywhere. Engineers use them to model forces and currents. Economists use them to balance supply and demand. Computer scientists rely on them in machine learning, rendering, and network analysis. Understanding how to solve a system of equations is one of the most practical skills in mathematics.

This free system of equations solver handles both 2×2 and 3×3 linear systems, shows every step, and accepts any real-valued coefficients — no registration or download required.

How to Use This System Solver

  1. Choose your system size. Select a 2×2 system (two equations, two unknowns) or a 3×3 system (three equations, three unknowns) from the toggle above the solver.
  2. Enter the coefficients. Type the values for a₁, b₁, c₁ (and a₂, b₂, c₂, etc.) into the labelled fields. Each row represents one equation in the form ax + by = c.
  3. Click Solve. The linear equation system calculator will instantly compute the solution.
  4. Review the step-by-step breakdown. The result panel shows each stage of the chosen method so you can follow along and learn, not just copy an answer.

For the algebra system solver to work correctly, make sure all equations are in standard form with numeric coefficients. Fractions and negative numbers are fully supported.

Three Methods for Solving Linear Systems

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Substitution Method

Isolate one variable in one equation — for example, express y in terms of x — then substitute that expression into the second equation. The result is a single equation in one unknown, which you solve directly. The substitution method calculator is ideal for 2×2 systems where one coefficient is already 1 or −1.

Elimination Method

Multiply one or both equations by constants so that the coefficient of one variable matches in magnitude, then add or subtract the equations to cancel that variable. The elimination method calculator is efficient when coefficients are easy to match and scales naturally to larger systems through row reduction.

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Matrix Method (Cramer’s Rule)

Arrange the coefficients into a coefficient matrix A and a constants vector b. Each variable is then the ratio of two determinants. This matrix method solver is compact and scales cleanly to 3×3 systems, making it a standard technique in engineering and scientific computing.

Worked Examples

Example 1: 2×2 System

Solve the following system using the 2×2 system solver:

2x + y = 7

x − y = 2

Solving by elimination:

  • Add both equations: 3x = 9x = 3
  • Substitute back: 3 − y = 2y = 1

Solution: x = 3, y = 1 — confirmed by the intersection point (3, 1) in the graph above.


Example 2: 3×3 System

Solve the following system using the 3×3 system solver:

x + y + z = 6

2x − y + z = 3

−x + y + 2z = 7

Step-by-step (elimination):

  • Subtract Eq 1 from Eq 2 ×1: x − 2y = −3 (new Eq A)
  • Add Eq 1 and Eq 3: 2y + 3z = 13 (new Eq B)
  • From Eq A and Eq B, eliminate y to find z = 3
  • Back-substitute: y = 2, then x = 1

Solution: x = 1, y = 2, z = 3 — enter these values into the linear equations solver with steps above to verify.

System Equations Solution
2×2 2x + y = 7  |  x − y = 2 x = 3, y = 1
3×3 x+y+z=6  |  2x−y+z=3  |  −x+y+2z=7 x = 1, y = 2, z = 3

Frequently Asked Questions

A system of equations is a set of two or more equations that share the same variables. A solution to the system is an assignment of values to those variables that makes every equation in the set true simultaneously. In a linear system solver, each equation defines a line (in 2D) or a plane (in 3D), and the solution is their intersection.
A 2×2 system has two equations and two unknowns (usually x and y). You can solve it by substitution (express one variable in terms of the other and substitute), by elimination (add or subtract scaled equations to cancel a variable), or by using a linear equation system calculator that applies Cramer’s rule with a 2×2 determinant.
The elimination method (also called the addition method) works by multiplying one or both equations by constants so that the coefficient of one variable is the same magnitude in both. Adding or subtracting the equations then eliminates that variable, leaving a single equation with one unknown. The elimination method calculator automates this process and displays each multiplication and addition step.
The substitution method involves isolating one variable in one equation — for example, writing y = 7 − 2x — and substituting that expression into the other equation. This reduces the system to a single equation with one unknown. The substitution method calculator is especially straightforward when a coefficient is already ±1.
Yes. Our 3×3 system solver accepts three equations with three unknowns (x, y, and z). It applies Gaussian elimination or Cramer’s rule on the 3×3 coefficient matrix and outputs a complete step-by-step solution. If the system is inconsistent (no solution) or dependent (infinitely many solutions), the solver will report that as well.
The matrix method represents the system as Ax = b, where A is the coefficient matrix and b is the column of constants. Cramer’s rule then solves for each variable as the ratio of two determinants: the determinant of a modified matrix over the determinant of A. This matrix method solver is compact and scales predictably, making it popular in scientific and engineering applications.

Ready to Solve Your System?

Whether you’re working through a homework problem, checking engineering calculations, or exploring linear algebra concepts, our free system of equations solver gives you accurate results and a clear explanation of every step. No guesswork, no hidden fees — just fast, reliable answers from a trusted algebra system solver.

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